Physics

6. Torque

Rotational force causing objects to rotate around an axis

Definitions

Torque (τ)

  • A measure of rotational force applied to an object that causes it to rotate around an axis, measured in N⋅m
τ=r×F\vec{\tau} = \vec{r} \times \vec{F}

where r\vec{r} is the position vector from the axis to the point of force application, and F\vec{F} is the applied force

Rotational Equation of Motion

  • The rotational analogue of Newton's second law
τ=Iα\vec{\tau} = I \alpha

 

Derivations

consider a force (F\vec{F}) acting on a particle (mass mm, distance from axis rr) that causes it to accelerate around an axis

F=mat\vec{F} = ma_t

since the tangential acceleration is related to angular acceleration by

at=αra_t = \alpha r

substituting this expression

F=mrα\vec{F} = m r \alpha

multiply both sides by rr

Fr=mr2α\vec{F}r = m r^2 \alpha

recognizing that Fr=τ\vec{F}r = \vec{\tau} and mr2=Imr^2 = I

τ=Iα\vec{\tau} = I \alpha

 

Useful Equations

τ=r×F,τ=Iα\vec{\tau} = \vec{r} \times \vec{F}, \quad \vec{\tau} = I \alpha

 

Example 1

A force of 10 N is applied perpendicular to a wrench at a distance of 0.3 m from the bolt. What is the torque applied to the bolt?

Answer

Using τ=rF\tau = rF (for perpendicular force)

τ=0.3×10=3 N⋅m\tau = 0.3 \times 10 = 3 \text{ N⋅m}

 

Example 2

A wheel with moment of inertia 2 kg⋅m² experiences a torque of 8 N⋅m. What is its angular acceleration?

Answer

Using τ=Iα\tau = I\alpha

α=τI=82=4 rad/s2\alpha = \frac{\tau}{I} = \frac{8}{2} = 4 \text{ rad/s}^2