Physics
Level 1/Oscillations

4. Pendulums

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Definitions

Torsional Pendulum

  • A system twisted by a small angular displacement θ\theta due to torque

Simple Pendulum

  • A system consisting of a point mass suspended by a rod or string of negligible mass

Derivations

Torsional Pendulum

Torsional Pendulum

We define

τz=kθ\tau_z = -k\theta

where kk is the torsion constant

since

τz=Iαz=Iθ¨\tau_z = I\alpha_z = I\ddot{\theta}

equating τz\tau_z

θ¨=kIθ\ddot{\theta} = -\dfrac{k}{I} \theta

this is in the form of SMH therefore

ω2=kI,ω=kI\omega^2 = \dfrac{k}{I}, \quad \omega = \sqrt{\dfrac{k}{I}}

 

Simple Pendulum

Simple Pendulum

We can see that

sin(θ)=xLsin(\theta) = \dfrac{x}{L}

where θ\theta is in radians

assuming θ\theta is small

θxL\theta \approx \dfrac{x}{L}

therefore the restoring force is

FmgxLF \approx -mg \dfrac{x}{L}

since mgL\dfrac{mg}{L} is constant we define kk as this constant such that

FkxF \approx -kx

solving for ω\omega, we can divide both sides by mm

a=kmxa = -\dfrac{k}{m}x

therefore

ω=km\omega = \sqrt{\dfrac{k}{m}}

subbing k=mgLk = \dfrac{mg}{L}

ω=gL\omega = \sqrt{\dfrac{g}{L}}

Why don't we account for tension TT

  • String doesn't change length
  • Bob moves in a circular arc
  • So tension is always perpendicular to displacement
Ts=0T \cdot s = 0

where ss is the displacement along the path (arc length)

therefore no work done by tension